Optimal. Leaf size=123 \[ \frac{\left (a^2+4 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac{\left (a^2-2 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 d}+\frac{2 a b \cot (c+d x)}{3 d}-\frac{a b \cot (c+d x) \csc ^2(c+d x)}{6 d}-\frac{\cot (c+d x) \csc ^3(c+d x) (a+b \sin (c+d x))^2}{4 d} \]
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Rubi [A] time = 0.364544, antiderivative size = 123, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.276, Rules used = {2889, 3048, 3031, 3021, 2748, 3767, 8, 3770} \[ \frac{\left (a^2+4 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac{\left (a^2-2 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 d}+\frac{2 a b \cot (c+d x)}{3 d}-\frac{a b \cot (c+d x) \csc ^2(c+d x)}{6 d}-\frac{\cot (c+d x) \csc ^3(c+d x) (a+b \sin (c+d x))^2}{4 d} \]
Antiderivative was successfully verified.
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Rule 2889
Rule 3048
Rule 3031
Rule 3021
Rule 2748
Rule 3767
Rule 8
Rule 3770
Rubi steps
\begin{align*} \int \cot ^2(c+d x) \csc ^3(c+d x) (a+b \sin (c+d x))^2 \, dx &=\int \csc ^5(c+d x) (a+b \sin (c+d x))^2 \left (1-\sin ^2(c+d x)\right ) \, dx\\ &=-\frac{\cot (c+d x) \csc ^3(c+d x) (a+b \sin (c+d x))^2}{4 d}+\frac{1}{4} \int \csc ^4(c+d x) (a+b \sin (c+d x)) \left (2 b-a \sin (c+d x)-3 b \sin ^2(c+d x)\right ) \, dx\\ &=-\frac{a b \cot (c+d x) \csc ^2(c+d x)}{6 d}-\frac{\cot (c+d x) \csc ^3(c+d x) (a+b \sin (c+d x))^2}{4 d}-\frac{1}{12} \int \csc ^3(c+d x) \left (3 \left (a^2-2 b^2\right )+8 a b \sin (c+d x)+9 b^2 \sin ^2(c+d x)\right ) \, dx\\ &=\frac{\left (a^2-2 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 d}-\frac{a b \cot (c+d x) \csc ^2(c+d x)}{6 d}-\frac{\cot (c+d x) \csc ^3(c+d x) (a+b \sin (c+d x))^2}{4 d}-\frac{1}{24} \int \csc ^2(c+d x) \left (16 a b+3 \left (a^2+4 b^2\right ) \sin (c+d x)\right ) \, dx\\ &=\frac{\left (a^2-2 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 d}-\frac{a b \cot (c+d x) \csc ^2(c+d x)}{6 d}-\frac{\cot (c+d x) \csc ^3(c+d x) (a+b \sin (c+d x))^2}{4 d}-\frac{1}{3} (2 a b) \int \csc ^2(c+d x) \, dx-\frac{1}{8} \left (a^2+4 b^2\right ) \int \csc (c+d x) \, dx\\ &=\frac{\left (a^2+4 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac{\left (a^2-2 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 d}-\frac{a b \cot (c+d x) \csc ^2(c+d x)}{6 d}-\frac{\cot (c+d x) \csc ^3(c+d x) (a+b \sin (c+d x))^2}{4 d}+\frac{(2 a b) \operatorname{Subst}(\int 1 \, dx,x,\cot (c+d x))}{3 d}\\ &=\frac{\left (a^2+4 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac{2 a b \cot (c+d x)}{3 d}+\frac{\left (a^2-2 b^2\right ) \cot (c+d x) \csc (c+d x)}{8 d}-\frac{a b \cot (c+d x) \csc ^2(c+d x)}{6 d}-\frac{\cot (c+d x) \csc ^3(c+d x) (a+b \sin (c+d x))^2}{4 d}\\ \end{align*}
Mathematica [B] time = 6.17054, size = 579, normalized size = 4.71 \[ \frac{\left (a^2-4 b^2\right ) \sin ^2(c+d x) \csc ^2\left (\frac{1}{2} (c+d x)\right ) (a \csc (c+d x)+b)^2}{32 d (a+b \sin (c+d x))^2}+\frac{\left (-a^2-4 b^2\right ) \sin ^2(c+d x) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right ) (a \csc (c+d x)+b)^2}{8 d (a+b \sin (c+d x))^2}+\frac{\left (4 b^2-a^2\right ) \sin ^2(c+d x) \sec ^2\left (\frac{1}{2} (c+d x)\right ) (a \csc (c+d x)+b)^2}{32 d (a+b \sin (c+d x))^2}+\frac{\left (a^2+4 b^2\right ) \sin ^2(c+d x) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right ) (a \csc (c+d x)+b)^2}{8 d (a+b \sin (c+d x))^2}-\frac{a^2 \sin ^2(c+d x) \csc ^4\left (\frac{1}{2} (c+d x)\right ) (a \csc (c+d x)+b)^2}{64 d (a+b \sin (c+d x))^2}+\frac{a^2 \sin ^2(c+d x) \sec ^4\left (\frac{1}{2} (c+d x)\right ) (a \csc (c+d x)+b)^2}{64 d (a+b \sin (c+d x))^2}-\frac{a b \sin ^2(c+d x) \cot \left (\frac{1}{2} (c+d x)\right ) \csc ^2\left (\frac{1}{2} (c+d x)\right ) (a \csc (c+d x)+b)^2}{12 d (a+b \sin (c+d x))^2}+\frac{a b \sin ^2(c+d x) \cot \left (\frac{1}{2} (c+d x)\right ) (a \csc (c+d x)+b)^2}{3 d (a+b \sin (c+d x))^2}-\frac{a b \sin ^2(c+d x) \tan \left (\frac{1}{2} (c+d x)\right ) (a \csc (c+d x)+b)^2}{3 d (a+b \sin (c+d x))^2}+\frac{a b \sin ^2(c+d x) \tan \left (\frac{1}{2} (c+d x)\right ) \sec ^2\left (\frac{1}{2} (c+d x)\right ) (a \csc (c+d x)+b)^2}{12 d (a+b \sin (c+d x))^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.082, size = 173, normalized size = 1.4 \begin{align*} -{\frac{{a}^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4\,d \left ( \sin \left ( dx+c \right ) \right ) ^{4}}}-{\frac{{a}^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{8\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2}}}-{\frac{{a}^{2}\cos \left ( dx+c \right ) }{8\,d}}-{\frac{{a}^{2}\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{8\,d}}-{\frac{2\,ab \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{3\,d \left ( \sin \left ( dx+c \right ) \right ) ^{3}}}-{\frac{{b}^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{2\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2}}}-{\frac{{b}^{2}\cos \left ( dx+c \right ) }{2\,d}}-{\frac{{b}^{2}\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{2\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.06572, size = 174, normalized size = 1.41 \begin{align*} -\frac{3 \, a^{2}{\left (\frac{2 \,{\left (\cos \left (d x + c\right )^{3} + \cos \left (d x + c\right )\right )}}{\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1} - \log \left (\cos \left (d x + c\right ) + 1\right ) + \log \left (\cos \left (d x + c\right ) - 1\right )\right )} - 12 \, b^{2}{\left (\frac{2 \, \cos \left (d x + c\right )}{\cos \left (d x + c\right )^{2} - 1} + \log \left (\cos \left (d x + c\right ) + 1\right ) - \log \left (\cos \left (d x + c\right ) - 1\right )\right )} + \frac{32 \, a b}{\tan \left (d x + c\right )^{3}}}{48 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.4891, size = 504, normalized size = 4.1 \begin{align*} -\frac{32 \, a b \cos \left (d x + c\right )^{3} \sin \left (d x + c\right ) + 6 \,{\left (a^{2} - 4 \, b^{2}\right )} \cos \left (d x + c\right )^{3} + 6 \,{\left (a^{2} + 4 \, b^{2}\right )} \cos \left (d x + c\right ) - 3 \,{\left ({\left (a^{2} + 4 \, b^{2}\right )} \cos \left (d x + c\right )^{4} - 2 \,{\left (a^{2} + 4 \, b^{2}\right )} \cos \left (d x + c\right )^{2} + a^{2} + 4 \, b^{2}\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 3 \,{\left ({\left (a^{2} + 4 \, b^{2}\right )} \cos \left (d x + c\right )^{4} - 2 \,{\left (a^{2} + 4 \, b^{2}\right )} \cos \left (d x + c\right )^{2} + a^{2} + 4 \, b^{2}\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right )}{48 \,{\left (d \cos \left (d x + c\right )^{4} - 2 \, d \cos \left (d x + c\right )^{2} + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.22435, size = 246, normalized size = 2. \begin{align*} \frac{3 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 16 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 24 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 48 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 24 \,{\left (a^{2} + 4 \, b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) + \frac{50 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 200 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 48 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 24 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 16 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 3 \, a^{2}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4}}}{192 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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